V. 2D Portal Reactions Sidesway 1
To find the displacements at the nodes of a frame due to movements of supports.
Reference
C.K. Wang, Intermediate Structural Analysis, International Student Edition, 1983, McGraw Hill, Section 2.11, p47.
Problem
Calculate the deflections at node B and support D.
Frame subject to imposed displacements
Load Cases:
- Vertical displacement of 1 cm at Node A
- Vertical displacement of 1 cm at Node B
Comparison
Result Type | Theory | STAAD.Pro | Difference | Comment | |
---|---|---|---|---|---|
Load Case 1 | Horizontal displacement at node B (cm) | 1.25 | -1.25 | none | Different orientation of positive axis results in different sign. |
Rotation at node B | 0.001667 | 0.0017 | none | ||
Horizontal displacement at node D (cm) | 0.4167 | -0.4167 | none | Different orientation of positive axis results in different sign. | |
Load Case 2 | Horizontal displacement at node B (cm) | 1.25 | 1.25 | none | |
Rotation at node B | 0.001667 | 0.0017 | none | ||
Horizontal displacement at node D (cm) | 0.4167 | 0.4167 | none |
STAAD Input
The file C:\Users\Public\Public Documents\STAAD.Pro 2023\Samples \Verification Models\03 Frames\2D Portal Reactions Sidesway 1.STD is typically installed with the program.
STAAD PLANE DEFLECTIONS DUE TO MOVEMENT OF SUPPORTS
START JOB INFORMATION
ENGINEER DATE 17-Sep-18
END JOB INFORMATION
*
* REFERENCE: INTERMEDIATE STRUCTURAL ANALYSIS, C.K.WANG
* INTERNATIONAL STUDENT EDITION, 1983, MCGRAW HILL
* SECTION 2.11, PAGE 47
*
UNIT METER KN
JOINT COORDINATES
1 0 0 0; 2 0 7.5 0; 3 6 7.5 0; 4 6 2.5 0;
MEMBER INCIDENCES
1 1 2; 2 2 3; 3 3 4;
UNIT CM KN
MEMBER PROPERTY AMERICAN
1 3 PRIS AX 2400 IZ 720000
2 PRIS AX 4800 IZ 1.44e+06
DEFINE MATERIAL START
ISOTROPIC MATERIAL1
E 2171.84
POISSON 0.17
END DEFINE MATERIAL
CONSTANTS
MATERIAL MATERIAL1 ALL
SUPPORTS
1 PINNED
4 FIXED BUT FX MZ
LOAD 1
SUPPORT DISPLACEMENT LOAD
1 FY -1
LOAD 2
SUPPORT DISPLACEMENT LOAD
4 FY -1
PERFORM ANALYSIS
LOAD LIST 1
PRINT JOINT DISPLACEMENTS
LOAD LIST 2
PRINT JOINT DISPLACEMENTS
FINISH
STAAD Output
JOINT DISPLACEMENT (CM RADIANS) STRUCTURE TYPE = PLANE ------------------ JOINT LOAD X-TRANS Y-TRANS Z-TRANS X-ROTAN Y-ROTAN Z-ROTAN 1 1 0.0000 -1.0000 0.0000 0.0000 0.0000 0.0017 2 1 -1.2500 -1.0000 0.0000 0.0000 0.0000 0.0017 3 1 -1.2500 0.0000 0.0000 0.0000 0.0000 0.0017 4 1 -0.4167 0.0000 0.0000 0.0000 0.0000 0.0017 ************** END OF LATEST ANALYSIS RESULT ************** 38. LOAD LIST 2 39. PRINT JOINT DISPLACEMENTS JOINT DISPLACE DEFLECTIONS DUE TO MOVEMENT OF SUPPORTS -- PAGE NO. 4 JOINT DISPLACEMENT (CM RADIANS) STRUCTURE TYPE = PLANE ------------------ JOINT LOAD X-TRANS Y-TRANS Z-TRANS X-ROTAN Y-ROTAN Z-ROTAN 1 2 0.0000 0.0000 0.0000 0.0000 0.0000 -0.0017 2 2 1.2500 0.0000 0.0000 0.0000 0.0000 -0.0017 3 2 1.2500 -1.0000 0.0000 0.0000 0.0000 -0.0017 4 2 0.4167 -1.0000 0.0000 0.0000 0.0000 -0.0017