EX. UK-13 Section Displacements for a Frame
Calculation of displacements at intermediate points of members of a plane frame is demonstrated in this example.
This problem is installed with the program by default to C:\Users\Public\Public Documents\STAAD.Pro CONNECT Edition\Samples\Sample Models\UK\UK-13 Section Displacements for a Frame.STD when you install the program.
- L1 = 4.5 m, L2 = 6.0 m
- P = 25 kN
- w = 45 kN/m
The dashed line represents the deflected shape of the structure. The shape is generated on the basis of displacements at the ends plus several intermediate points of the members.
Actual input is shown in bold lettering followed by explanation.
STAAD PLANE TEST FOR SECTION DISPLACEMENT
Every input has to start with the term STAAD. The term PLANE signifies that the structure is a plane frame structure and the geometry is defined through X and Y axes.
UNIT METER KNS
Defines the input units for the data that follows.
JOINT COORDINATES
1 0 0 ; 2 0. 4.5 ; 3 6 4.5 ; 4 6 0.
Joint number followed by X and Y coordinates are provided above. Since this is a plane structure, the Z coordinates need not be provided.
MEMBER INCIDENCE
1 1 2 ; 2 2 3 ; 3 3 4
Defines the members by the joints to which they are connected.
MEMBER PROPERTY BRITISH
1 3 TABLE ST UC203X203X46
2 TABLE ST UB305X165X40
Member properties are specified from the British steel table. The word ST stands for standard single section.
UNIT MMS
DEFINE MATERIAL START
ISOTROPIC STEEL
E 210
POISSON 0.3
DENSITY 7.6977e-008
ALPHA 6e-006
DAMP 0.03
TYPE STEEL
STRENGTH FY 0.25 FU 0.4 RY 1.5 RT 1.2
END DEFINE MATERIAL
CONSTANTS
MATERIAL STEEL ALL
The length unit is changed from METER to MMS. The DEFINE MATERIAL command is used to specify material properties and the CONSTANT is used to assign the material to all members.
SUPPORT
1 FIXED ; 4 PINNED
A fixed support is specified at Joint 1 and a pinned support at Joint 4.
UNIT METER
LOADING 1 DEAD + LIVE + WIND
Load case 1 is initiated followed by an optional title.
JOINT LOAD
2 FX 25.0
Load 1 contains a joint load of 25KN at node 2. FX indicates that the load is a force in the global X direction.
MEMBER LOAD
2 UNI GY -45.0
Load 1 contains a member load also. GY indicates that the load is in the global Y direction. The word UNI stands for uniformly distributed load.
PERFORM ANALYSIS
This command instructs the program to proceed with the analysis.
PRINT MEMBER FORCES
The above PRINT command is self-explanatory.
*
* FOLLOWING PRINT COMMAND WILL PRINT
* DISPLACEMENTS OF THE MEMBERS
* CONSIDERING EVERY TWELFTH INTERMEDIATE
* POINT (THAT IS TOTAL OF 13 POINTS). THESE
* DISPLACEMENTS ARE MEASURED IN GLOBAL X
* Y Z COORDINATE SYSTEM AND THE VALUES
* ARE FROM ORIGINAL COORDINATES (UNDEFLECTED
* POSITION) OF CORRESPONDING TWELFTH
* POINTS.
*
* MAX LOCAL DISPLACEMENT IS ALSO PRINTED.
* THE LOCATION OF MAXIMUM INTERMEDIATE
* DISPLACEMENT IS DETERMINED. THIS VALUE IS
* MEASURED FROM ABOVE LOCATION TO THE
* STRAIGHT LINE JOINING START AND END
* JOINTS OF THE DEFLECTED MEMBER.
*
PRINT SECTION DISPLACEMENT
Above PRINT command is explained in the comment lines above.
FINISH
This command terminates the STAAD run.
Input File
STAAD PLANE TEST FOR SECTION DISPLACEMENT
UNIT METER KNS
JOINT COORDINATES
1 0.0 0.0 ; 2 0.0 4.5 ; 3 6.0 4.5 ; 4 6.0 0.0
MEMBER INCIDENCE
1 1 2 ; 2 2 3 ; 3 3 4
MEMBER PROPERTY BRITISH
1 3 TABLE ST UC203X203X46
2 TABLE ST UB305X165X40
UNIT MMS
DEFINE MATERIAL START
ISOTROPIC STEEL
E 210.0
POISSON 0.3
DENSITY 7.6977e-008
ALPHA 6e-006
DAMP 0.03
TYPE STEEL
STRENGTH FY 0.25 FU 0.4 RY 1.5 RT 1.2
END DEFINE MATERIAL
CONSTANTS
MATERIAL STEEL ALL
SUPPORT
1 FIXED ; 4 PINNED
UNIT METER
LOADING 1 DEAD + LIVE + WIND
JOINT LOAD
2 FX 25.0
MEMBER LOAD
2 UNI GY -45.0
PERFORM ANALYSIS
PRINT MEMBER FORCES
*
* FOLLOWING PRINT COMMAND WILL PRINT
* DISPLACEMENTS OF THE MEMBERS CONSIDERING EVERY
* TWELFTH INTERMEDIATE POINT (THAT IS TOTAL OF 13 POINTS).
* THESE DISPLACEMENTS ARE MEASURED IN GLOBAL X Y Z
* COORDINATE SYSTEM AND THE VALUES ARE FROM
* ORIGINAL COORDINATES (UNDEFLECTED POSITION)
* OF THE CORRESPONDING TWELFTH POINTS.
*
* MAX LOCAL DISPLACEMENT IS ALSO PRINTED. THE
* LOCATION OF MAXIMUM INTERMEDIATE DISPLACEMENT
* IS DETERMINED. THIS VALUE IS MEASURED FROM ABOVE
* LOCATION TO THE STRAIGHT LINE JOINING START AND
* END JOINTS OF THE DEFLECTED MEMBER.
*
PRINT SECTION DISPLACEMENT
FINISH
STAAD Output File
PAGE NO. 1 **************************************************** * * * STAAD.Pro CONNECT Edition * * Version 22.12.00.*** * * Proprietary Program of * * Bentley Systems, Inc. * * Date= OCT 27, 2022 * * Time= 15: 7:10 * * * * Licensed to: Bentley Systems Inc * **************************************************** 1. STAAD PLANE TEST FOR SECTION DISPLACEMENT INPUT FILE: UK-13 Section Displacements for a Frame.STD 2. UNIT METER KNS 3. JOINT COORDINATES 4. 1 0.0 0.0 ; 2 0.0 4.5 ; 3 6.0 4.5 ; 4 6.0 0.0 5. MEMBER INCIDENCE 6. 1 1 2 ; 2 2 3 ; 3 3 4 7. MEMBER PROPERTY BRITISH 8. 1 3 TABLE ST UC203X203X46 9. 2 TABLE ST UB305X165X40 10. UNIT MMS 11. DEFINE MATERIAL START 12. ISOTROPIC STEEL 13. E 210.0 14. POISSON 0.3 15. DENSITY 7.6977E-008 16. ALPHA 6E-006 17. DAMP 0.03 18. TYPE STEEL 19. STRENGTH FY 0.25 FU 0.4 RY 1.5 RT 1.2 20. END DEFINE MATERIAL 21. CONSTANTS 22. MATERIAL STEEL ALL 23. SUPPORT 24. 1 FIXED ; 4 PINNED 25. UNIT METER 26. LOADING 1 DEAD + LIVE + WIND 27. JOINT LOAD 28. 2 FX 25.0 29. MEMBER LOAD 30. 2 UNI GY -45.0 31. PERFORM ANALYSIS TEST FOR SECTION DISPLACEMENT -- PAGE NO. 2 P R O B L E M S T A T I S T I C S ----------------------------------- NUMBER OF JOINTS 4 NUMBER OF MEMBERS 3 NUMBER OF PLATES 0 NUMBER OF SOLIDS 0 NUMBER OF SURFACES 0 NUMBER OF SUPPORTS 2 Using 64-bit analysis engine. SOLVER USED IS THE IN-CORE ADVANCED MATH SOLVER TOTAL PRIMARY LOAD CASES = 1, TOTAL DEGREES OF FREEDOM = 7 TOTAL LOAD COMBINATION CASES = 0 SO FAR. 32. PRINT MEMBER FORCES MEMBER FORCES TEST FOR SECTION DISPLACEMENT -- PAGE NO. 3 MEMBER END FORCES STRUCTURE TYPE = PLANE ----------------- ALL UNITS ARE -- KNS METE (LOCAL ) MEMBER LOAD JT AXIAL SHEAR-Y SHEAR-Z TORSION MOM-Y MOM-Z 1 1 1 121.84 1.65 0.00 0.00 0.00 33.54 2 -121.84 -1.65 0.00 0.00 0.00 -26.10 2 1 2 23.35 121.84 0.00 0.00 0.00 26.10 3 -23.35 148.16 0.00 0.00 0.00 -105.06 3 1 3 148.16 23.35 0.00 0.00 0.00 105.06 4 -148.16 -23.35 0.00 0.00 0.00 -0.00 ************** END OF LATEST ANALYSIS RESULT ************** 33. * 34. * FOLLOWING PRINT COMMAND WILL PRINT 35. * DISPLACEMENTS OF THE MEMBERS CONSIDERING EVERY 36. * TWELFTH INTERMEDIATE POINT (THAT IS TOTAL OF 13 POINTS). 37. * THESE DISPLACEMENTS ARE MEASURED IN GLOBAL X Y Z 38. * COORDINATE SYSTEM AND THE VALUES ARE FROM 39. * ORIGINAL COORDINATES (UNDEFLECTED POSITION) 40. * OF THE CORRESPONDING TWELFTH POINTS. 41. * 42. * MAX LOCAL DISPLACEMENT IS ALSO PRINTED. THE 43. * LOCATION OF MAXIMUM INTERMEDIATE DISPLACEMENT 44. * IS DETERMINED. THIS VALUE IS MEASURED FROM ABOVE 45. * LOCATION TO THE STRAIGHT LINE JOINING START AND 46. * END JOINTS OF THE DEFLECTED MEMBER. 47. * 48. PRINT SECTION DISPLACEMENT SECTION DISPLACE TEST FOR SECTION DISPLACEMENT -- PAGE NO. 4 MEMBER SECTION DISPLACEMENTS ---------------------------- UNITS ARE - CM MEMB LOAD GLOBAL X,Y,Z DISPL FROM START TO END JOINTS AT 1/12TH PTS 1 1 0.0000 0.0000 0.0000 0.0249 -0.0037 0.0000 0.0981 -0.0074 0.0000 0.2187 -0.0111 0.0000 0.3856 -0.0148 0.0000 0.5981 -0.0185 0.0000 0.8552 -0.0222 0.0000 1.1560 -0.0260 0.0000 1.4996 -0.0297 0.0000 1.8850 -0.0334 0.0000 2.3115 -0.0371 0.0000 2.7780 -0.0408 0.0000 3.2836 -0.0445 0.0000 MAX LOCAL DISP = 0.78662 AT 225.00 LOAD 1 L/DISP= 572 2 1 3.2836 -0.0445 0.0000 3.2825 -0.7367 0.0000 3.2814 -1.3907 0.0000 3.2804 -1.9447 0.0000 3.2793 -2.3529 0.0000 3.2782 -2.5850 0.0000 3.2771 -2.6266 0.0000 3.2760 -2.4791 0.0000 3.2749 -2.1595 0.0000 3.2739 -1.7007 0.0000 3.2728 -1.1514 0.0000 3.2717 -0.5758 0.0000 3.2706 -0.0541 0.0000 MAX LOCAL DISP = 2.57728 AT 300.00 LOAD 1 L/DISP= 232 3 1 3.2706 -0.0541 0.0000 3.5390 -0.0496 0.0000 3.6663 -0.0451 0.0000 3.6653 -0.0406 0.0000 3.5488 -0.0361 0.0000 3.3297 -0.0316 0.0000 3.0208 -0.0271 0.0000 2.6349 -0.0225 0.0000 2.1849 -0.0180 0.0000 1.6836 -0.0135 0.0000 1.1438 -0.0090 0.0000 0.5783 -0.0045 0.0000 0.0000 0.0000 0.0000 MAX LOCAL DISP = 1.42182 AT 187.50 LOAD 1 L/DISP= 316 ************ END OF SECT DISPL RESULTS *********** 49. FINISH TEST FOR SECTION DISPLACEMENT -- PAGE NO. 5 *********** END OF THE STAAD.Pro RUN *********** **** DATE= OCT 27,2022 TIME= 15: 7:11 **** ************************************************************ * For technical assistance on STAAD.Pro, please visit * * http://www.bentley.com/en/support/ * * * * Details about additional assistance from * * Bentley and Partners can be found at program menu * * Help->Technical Support * * * * Copyright (c) Bentley Systems, Inc. * * http://www.bentley.com * ************************************************************