where

Cv	=	$\frac{45,000k}{F_y{(h/t)}^2}$ when h/b ≤ 0.8 $=\frac{190}{h/t}\sqrt{\frac{k}{F_y}}$ when h/b > 0.8
k	=	4.00 + 5.34/(a/h)2 when a/h ≤ 1.0 = 5.34 + 4.00/(a/h)2 when a/h > 1.0

For actual shear on the web, the gross section is taken as the product of the total depth and the web thickness. For shear on the flanges, the gross section is taken as the total flange areas.