Find the maximum axial force and moment due to load
and moment applied at a joint in a Space frame.
Reference
Weaver Jr., W.,
Computer Programs for Structural Analysis, page
146, problem 8.
Problem
Determine the maximum axial force and moment in the space
structure.
F = 2 kip, P = 1 kip, M = 120
in·kip
| |
Space frame
model
Comparison
Table 1. Comparison of results
Result Type
|
Theory
|
Advanced Analysis
|
Difference
|
FMax
(kips)
|
1.47
|
1.47
|
|
MY,
Max
(in·kip)
|
84.04
|
84.04
|
|
MZ,
Max
(in·kip)
|
95.319
|
95.32
|
|
STAAD Output
JOINT DISPLACEMENT (INCH RADIANS) STRUCTURE TYPE = SPACE
------------------
JOINT LOAD X-TRANS Y-TRANS Z-TRANS X-ROTAN Y-ROTAN Z-ROTAN
1 1 0.22267 0.00016 -0.17182 -0.00255 0.00217 -0.00213
2 1 0.22202 -0.48119 -0.70161 -0.00802 0.00101 -0.00435
3 1 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000
4 1 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000
: 3D FRAME MAX FORCES -- PAGE NO. 4
SUPPORT REACTIONS -UNIT KIP INCH STRUCTURE TYPE = SPACE
-----------------
JOINT LOAD FORCE-X FORCE-Y FORCE-Z MOM-X MOM-Y MOM Z
3 1 -1.10 -0.43 0.22 48.78 -17.97 96.12
4 1 -0.90 1.43 -0.22 123.08 47.25 -11.72
: 3D FRAME MAX FORCES -- PAGE NO. 5
MEMBER END FORCES STRUCTURE TYPE = SPACE
-----------------
ALL UNITS ARE -- KIP INCH (LOCAL )
MEMBER LOAD JT AXIAL SHEAR-Y SHEAR-Z TORSION MOM-Y MOM-Z
1 1 1 0.90 -0.43 0.22 22.71 -17.97 -36.37
2 -0.90 0.43 -0.22 -22.71 -34.18 -67.36
2 1 3 -0.43 1.10 0.22 -17.97 -48.78 96.12
1 0.43 -1.10 -0.22 17.97 22.71 36.37
3 1 2 1.47 -0.71 -0.48 -37.02 15.69 -53.28
4 -1.47 0.71 0.48 37.02 84.04 -95.32
************** END OF LATEST ANALYSIS RESULT **************
34. FINISH