V. 2D Portal Reactions Sidesway 1
To find the displacements at the nodes of a frame due to movements of supports.
Reference
C.K. Wang, Intermediate Structural Analysis, International Student Edition, 1983, McGraw Hill, Section 2.11, p47.
Problem
Calculate the deflections at node B and support D.
Frame subject to imposed displacements
Load Cases:
- Vertical displacement of 1 cm at Node A
- Vertical displacement of 1 cm at Node B
Comparison
Result Type | Theory | STAAD.Pro | Difference | |
---|---|---|---|---|
Load Case 1 | Horizontal displacement at node B (cm) | 1.25 | -1.25 | none |
Rotation at node B | 0.001667 | 0.0017 | none | |
Horizontal displacement at node D (cm) | 0.4167 | -0.4167 | none | |
Load Case 2 | Horizontal displacement at node B (cm) | 1.25 | 1.25 | none |
Rotation at node B | 0.001667 | 0.0017 | none | |
Horizontal displacement at node D (cm) | 0.4167 | 0.4167 | none |
STAAD Input
The file C:\Users\Public\Public Documents\STAAD.Pro CONNECT Edition\Samples\ Verification Models\03 Frames\2D Portal Reactions Sidesway 1.STD is typically installed with the program.
STAAD PLANE DEFLECTIONS DUE TO MOVEMENT OF SUPPORTS
START JOB INFORMATION
ENGINEER DATE 17-Sep-18
END JOB INFORMATION
*
* REFERENCE: INTERMEDIATE STRUCTURAL ANALYSIS, C.K.WANG
* INTERNATIONAL STUDENT EDITION, 1983, MCGRAW HILL
* SECTION 2.11, PAGE 47
*
UNIT METER KN
JOINT COORDINATES
1 0 0 0; 2 0 7.5 0; 3 6 7.5 0; 4 6 2.5 0;
MEMBER INCIDENCES
1 1 2; 2 2 3; 3 3 4;
UNIT CM KN
MEMBER PROPERTY AMERICAN
1 3 PRIS AX 2400 IZ 720000
2 PRIS AX 4800 IZ 1.44e+06
DEFINE MATERIAL START
ISOTROPIC MATERIAL1
E 2171.84
POISSON 0.17
END DEFINE MATERIAL
CONSTANTS
MATERIAL MATERIAL1 ALL
SUPPORTS
1 PINNED
4 FIXED BUT FX MZ
LOAD 1
SUPPORT DISPLACEMENT LOAD
1 FY -1
LOAD 2
SUPPORT DISPLACEMENT LOAD
4 FY -1
PERFORM ANALYSIS
LOAD LIST 1
PRINT JOINT DISPLACEMENTS
LOAD LIST 2
PRINT JOINT DISPLACEMENTS
FINISH
STAADÂ Output
JOINT DISPLACEMENT (CM RADIANS) STRUCTURE TYPE = PLANE ------------------ JOINT LOAD X-TRANS Y-TRANS Z-TRANS X-ROTAN Y-ROTAN Z-ROTAN 1 1 0.0000 -1.0000 0.0000 0.0000 0.0000 0.0017 2 1 -1.2500 -1.0000 0.0000 0.0000 0.0000 0.0017 3 1 -1.2500 0.0000 0.0000 0.0000 0.0000 0.0017 4 1 -0.4167 0.0000 0.0000 0.0000 0.0000 0.0017 ************** END OF LATEST ANALYSIS RESULT ************** 38. LOAD LIST 2 39. PRINT JOINT DISPLACEMENTS JOINT DISPLACE DEFLECTIONS DUE TO MOVEMENT OF SUPPORTS -- PAGE NO. 4 JOINT DISPLACEMENT (CM RADIANS) STRUCTURE TYPE = PLANE ------------------ JOINT LOAD X-TRANS Y-TRANS Z-TRANS X-ROTAN Y-ROTAN Z-ROTAN 1 2 0.0000 0.0000 0.0000 0.0000 0.0000 -0.0017 2 2 1.2500 0.0000 0.0000 0.0000 0.0000 -0.0017 3 2 1.2500 -1.0000 0.0000 0.0000 0.0000 -0.0017 4 2 0.4167 -1.0000 0.0000 0.0000 0.0000 -0.0017