 # D4.E.6.4 Members Subject to Shear

Factored shear resistance, Vr , developed by the web of flexural member is calculated as:

$V r = ϕ A w F s$
where
 Aw = shear area

Fs is evaluated as:

1. For unstiffened webs (Cl. 13.4.1.1.(a) ):

1. when $h w ≤ 1 , 014 F y$, Fs = 0.66Fy

2. when $1 , 014 F y < h w ≤ 1 , 435 F y$, $F s = 670 F y ( h / w )$

3. when $h w > 1 , 436 F y$, $F s = 961 , 200 ( h / w ) 2$

2. For stiffened webs (i.e., when the STIFF parameter is specified) (Cl. 13.4.1.1(b) ):

1. when $h w ≤ 439 k v F y$, Fs = 0.66Fy

2. when $439 k v F y < h w ≤ 502 k v F y$, Fs = Fcri

3. when $502 k v F y < h w ≤ 621 k v F y$, Fs = Fcri + ka(0.50Fy - 0.866Fcri)

4. when $621 k v F y < h w$, Fs = Fcre + ka(0.50Fy - 0.866Fcre)

where
 Ae = shear buckling coefficient: when a/h < 1, $k v = 4 + 5.34 ( a / h ) 2$ when a/h ≥ 1, $k v = 5.34 + 4 ( a / h ) 2$ a/h = stiffener aspect ration (i.e., ratio of the distance between stiffeners to web depth) Fcri = $290 F y k v ( h / w )$ ka = aspect coefficient = $1 1 + ( a / h ) 2$ Fcre = $180 , 000 k v ( h / w ) 2$

For tubular members, the shear resistance, Vr , is calculated as:

$V r = 0.66 ϕ ( A e / 2 ) F y$
where
 Ae = the cross-sectional area of the tubular member