Special Moment Frame
Flexural Reinforcement Design
- 21.3.2.1 - A minimum of 2 bars continuous top and bottom are required in all spans. Maximum and Minimum reinforcement ratios are set to:
r > 200 bw d / fy same as ACI eq 10-3 r ≤ 0.025 - 21.3.2.2 - Positive moment strength at a face is checked to be greater than or equal to 1/2 of the negative moment strength at that same face.
- 21.3.2.2 - The negative and positive moment strengths at any point along the beam must be at least 1/4 of the maximum moment strength (the greater of either the negative or the positive moment strength) provided at either face.
- 21.5.4.2 - Development Lengths for normal weight concrete shall not be less than:
- 21.3.2.3 -At splice locations transverse reinforcement must be provided with spacing equal to the smaller of d/4 or 4 in. Even though the optimization process tries to locate the splice near the center of the span the design/analyze process does not check the remainder of the provisions of section 21.3.2.3.
Note: It is advisable to set the Bar Spacing increment value under the Bar Selection tab of the Beam criteria dialog to a value of 1 in or 2 in so the reinforcement in the splice area is as large as possible. If the value is set to 3 in increment the user will end up with bar spacing in splice areas that is smaller than required by code.
For Bottom bars the development length is multiplied by 2.5 and for top reinforcement it is multiplied by 3.5. Note 1 - 21.5.4.3 is not implemented. Note 2 - It is the engineer's responsibility to set the Lap Splice type to Class B in the Detailing Defaults for Lateral beams.
Shear Design
- 21.3.4 - The beam shear capacity is designed to meet the larger of the analysis factored shear load Vu as well as the limiting shear induced at the end of the beam based on the members probable moment capacity Mpr as outlined in ACI R21.3.4.1
Vel = (M-prl + M-prr)/ln + Vu_max_l and Ver = (M+prl + M-prr)/ln + Vu_max_l Ver = (M+prl + M-prr)/ln + Vu_max_r and
whereVer = (M+prl + M-prr)/ln + Vu_max_r - V
= - Unfactored gravity shear at the ends of the member
- Mpr
= - a
= The program assumes that there is uniformly varying shear in between Vel and Ver. An additional shear diagram is created using the largest Vel for the left shear and Ver for right shear which are superimposed onto the shear envelop that was generated from the regular load combinations using the analysis shears. See Figure 5‑6 - Shear Diagrams. Note: Φ = 1 for the calculation of Mn.
- 21.3.4.2 - When the new required shear capacity Vu > Ve / 2 and Axial load < Ag F'c / 20 then the full shear in the section must be resisted by the shear reinforcement Vs. Note: This design constraint may produce two similar shear bar sets in the same beam spans with different shear capacities even though the transverse reinforcement bar size and spacing are identical. This is due to the fact that the capacity for one segment may include the concrete shear capacity because Vu is small enough and for the other segment it will not include the concrete shear capacity because Vu is too large.
- 21.3.3.1 a) and 21.3.3.2 - Hoops must be provided starting 2 inches from the face of the support to a distance of 2h.
- 21.3.3.4 - The remainder of the span must have hoops spacing of no more than d/2.